a) 8 × 5 × 9 = (8 × 5) × 9 = 40 × 9 = 360

b) 6 × 7 × 5 = (6 × 5) × 7= 30 × 7= 210

c) 6 × 4 × 25 = 6 × (4 × 25) = 6 × 100= 600

Phương pháp giải:

- Tính giá trị của phép nhân.

- Cộng với số còn lại.

- Trình bày bài theo mẫu.

Lời giải chi tiết:

a) 4 × 6 + 6 = 24 + 6 = 30

b) 4 × 7 + 12 = 28 + 12 = 40

c) 4 × 9 + 24 = 36 + 24 = 60

d) 4 × 2 + 32 = 8 + 32 = 40

a) 4 × 6 + 6 = 24 + 6 = 30

b) 4 × 7 + 12 = 28 + 12 = 40

c) 4 × 9 + 24 = 36 + 24 = 60

d) 4 × 2 + 32 = 8 + 32 = 40

a) \(\frac{9}{22}\cdot\frac{33}{8}=\frac{3^2\cdot3\cdot11}{2\cdot11\cdot2^3}=\frac{3^4}{2^4}=\frac{81}{16}\)

b) \(\frac{12}{35}:\frac{36}{35}=\frac{2^2\cdot3}{2^2\cdot3^2}=\frac{1}{3}\)

c) \(\frac{19}{17}:\frac{76}{51}=\frac{19\cdot3\cdot17}{17\cdot2^2\cdot19}=\frac{3}{4}\)

có mẫu đâu 

1.1) 6

 1.2) 1/6
 

\(3\div\frac{1}{2}=3\times\frac{2}{1}=6\)

\(\frac{1}{2}\div3=\frac{1}{2}\times\frac{1}{3}=\frac{1}{6}\)

2.Tính theo mẫu :

b) \(\frac{6}{25}\div\frac{21}{20}=\frac{6}{25}\times\frac{20}{21}=\frac{6\times20}{25\times21}=\frac{2\times3\times4\times5}{5\times5\times3\times7}=\frac{8}{35}\)

\(\frac{40}{7}\times\frac{14}{5}=\frac{40\times14}{7\times5}=\frac{5\times8\times7\times2}{7\times5}=16\)

\(\frac{17}{13}\div\frac{51}{26}=\frac{17}{13}\times\frac{26}{51}=\frac{17\times13\times2}{13\times17\times3}=\frac{2}{3}\)

Chúc bạn hok tốt !

Bài 1:

\(3:\frac{1}{2}=3x2=6\)

\(\frac{1}{2}:3=\frac{1}{2}x\frac{1}{3}=\frac{1}{6}\)

Bài 2L

b) \(\frac{6}{25}:\frac{21}{20}=\frac{6}{25}\times\frac{20}{21}=\frac{2\times3\times4\times5}{5\times5\times3\times7}=\frac{8}{7}\)

\(\frac{40}{7}\times\frac{14}{5}=\frac{8\times5\times2\times7}{7\times5}=16\)

\(\frac{17}{13}:\frac{51}{26}=\frac{17}{13}\times\frac{26}{51}=\frac{17\times2\times13}{13\times17\times3}=\frac{2}{3}\)

a: \(\dfrac{5}{6}\cdot7=\dfrac{5\cdot7}{6}=\dfrac{35}{6}\)

b: \(\dfrac{7}{10}\cdot3=\dfrac{7\cdot3}{10}=\dfrac{21}{10}\)

c: \(5\cdot\dfrac{4}{21}=\dfrac{5\cdot4}{21}=\dfrac{20}{21}\)

d: \(2\cdot\dfrac{5}{9}=\dfrac{2\cdot5}{9}=\dfrac{10}{9}\)

1: =72/90+65/90=137/90

2: =24/56-77/56=-53/56

3: =-7/10+4/5=1/10

4: =15/100-4/100=11/100

5: =4/6-5/6=-1/6

6: =10/40-15/40-76/40=-81/40

7: =-9/10+7/18

=-81/90+35/90=-46/90=-23/45

8: =27/90-55/90=-28/90=-14/45

9: =36/60-50/60-35/60=-49/60

10: =-4/9+5/6-3/8

=-32/72+60/72-27/72

=1/72

\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)

\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)

\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)

\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)

\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)

\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)

\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)

\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)

\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)

\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)

\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)

\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)

`@mt`

a, \(\left(\frac{4}{9}.\frac{3}{7}\right).\frac{7}{4}=\frac{4}{9}\left(\frac{3}{7}.\frac{7}{4}\right)=\frac{4}{9}.\frac{3}{4}=\frac{3}{9}=\frac{1}{3}\)

b, \(\left(\frac{6}{5}.\frac{4}{5}\right).\frac{25}{16}=\frac{6}{5}\left(\frac{4}{5}.\frac{25}{16}\right)=\frac{6}{5}.\frac{5}{4}=\frac{6}{4}=\frac{3}{2}\)

c, \(\left(\frac{7}{8}.\frac{16}{9}\right).\frac{3}{14}=\frac{7}{8}\left(\frac{16}{9}.\frac{3}{14}\right)=\frac{7}{8}.\frac{8}{21}=\frac{7}{21}=\frac{1}{3}\)

a, $\left(\frac{4}{9}.\frac{3}{7}\right).\frac{7}{4}=\frac{4}{9}\left(\frac{3}{7}.\frac{7}{4}\right)=\frac{4}{9}.\frac{3}{4}=\frac{3}{9}=\frac{1}{3}$

b, $(\frac{}{}$